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Modules over nilpotent group rings. (English) Zbl 0857.20002

In the representation theory of finitely generated nilpotent groups the use of induction leads one to consider impervious modules, those modules contain no non-zero submodules induced from a module over a subgroup of infinite index. Let \(H\) be a finitely generated nilpotent group with centre \(Z\) and let \(R\) be a commutative ring. Let \(H_0\) be a normal subgroup of \(H\) containing \(H'Z\) and with \(H_0/H'Z\) finite-by-cyclic. If \(M\) is an impervious \(RH\)-module of the group ring \(RH\) which is \(RZ/P\)-torsion-free for some prime ideal \(P\) of \(RZ\) with \((1+P)\cap Z=1\), then the authors prove that \(M\) is \(RH_0/PRH_0\)-torsion-free. This is the main result of this paper. Moreover, an impervious \(RH\)-module torsion-free over \(RZ\) is also torsion-free as an \(R(H'Z)\)-module. If \(R\) is the ring of integers and \(H\) is non-Abelian, then \(k\)-\(\dim(M)\geq h(H'Z)-h(Z)+2\). Here \(k\)-dim is the Krull dimension and \(h\) denotes the Hirsch length.
Let \(G\) be a weakly finitely presented Abelian-by-nilpotent group with Fitting subgroup \(F\). Suppose that some subgroup of \(G/F\) of finite index is a \(d\)-generator group. Then, applying the results above, the authors prove that some subgroup of \(G/F\) of finite index is of class at most \(d\).

MSC:

20C07 Group rings of infinite groups and their modules (group-theoretic aspects)
20F18 Nilpotent groups
16S34 Group rings
20E07 Subgroup theorems; subgroup growth
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