1824 United States presidential election in Alabama

The 1824 United States presidential election in Alabama took place between October 26 and December 2, 1824, as part of the 1824 presidential election. Voters chose five representatives, or electors, to the Electoral College, who voted for President and Vice President.

1824 United States presidential election in Alabama

← 1820 October 26 – December 2, 1824 1828 →

Nominee Andrew Jackson John Quincy Adams William H. Crawford Party Democratic-Republican Democratic-Republican Democratic-Republican Home state Tennessee Massachusetts Georgia Running mate John C. Calhoun John C. Calhoun Nathaniel Macon Electoral vote 5 0 0 Popular vote 9,429 2,422 1,656 Percentage 69.32% 17.80% 12.17%

County Results Jackson   40–50%   50–60%   70–80%   80–90%   90–100% Adams   40–50% Unknown/No Vote

President before election James Monroe Democratic-Republican Elected President John Quincy Adams Democratic-Republican

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Alabama voted for Andrew Jackson over John Quincy Adams, William H. Crawford and Henry Clay. Jackson won Alabama by a margin of 51.52%. This was the first time since achieving statehood in 1819 that Alabama backed the losing candidate in a presidential election.