OFFSET
1,3
COMMENTS
Conjecture: given the inverse Moebius transform operation performed any k times (k=1,2,3,...); k=24 is the only such sequence with zeros. A weaker conjecture: "zero" occurs an infinite number of times in A128382.
Multiplicative because A000594 is. Each application of A051731 corresponds to an inverse Moebius transform. - Andrew Howroyd, Aug 03 2018
LINKS
Andrew Howroyd, Table of n, a(n) for n = 1..1000
FORMULA
Dirichlet g.f.: Sum_{n>=1} a(n)/n^s = (Sum_{n>=1} A000594(n)/n^s)*zeta(s)^24. - Jianing Song, Aug 04 2018
MATHEMATICA
nmax = 40;
M = Table[If[Mod[n, k] == 0, 1, 0], {n, nmax}, {k, nmax}];
MatrixPower[M, 24].RamanujanTau[Range[nmax]] (* Jean-François Alcover, Sep 20 2019 *)
PROG
(PARI) seq(n, k=24)={my(u=vector(n, n, 1), v=vector(n, n, ramanujantau(n))); for(i=1, k, v=dirmul(u, v)); v} \\ Andrew Howroyd, Aug 03 2018
CROSSREFS
KEYWORD
sign,mult
AUTHOR
Gary W. Adamson, Feb 28 2007
EXTENSIONS
Terms a(11) and beyond from Andrew Howroyd, Aug 03 2018
STATUS
approved