1816 United States presidential election in Rhode Island

1816 United States presidential election in Rhode Island

← 1812 November 1 – December 4, 1816 1820 →

Nominee James Monroe Party Democratic-Republican Home state Virginia Running mate Daniel D. Tompkins Electoral vote 4 Popular vote 1,236 Percentage 100.00%

President before election James Madison Democratic-Republican Elected President James Monroe Democratic-Republican

Elections in Rhode Island
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Ballot measures 2020 Question 1
Providence Mayoral elections 1998 2002 2006 2010 2014 2018 2022
v t e

The 1816 United States presidential election in Rhode Island took place as part of the 1816 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College who voted for president and vice president.

Rhode Island voted for the Democratic-Republican candidate, James Monroe. Monroe won Rhode Island by a margin of 100.00%. Because the Federalist challenger in the nation, Rufus King, was not on the ballot.

• United States presidential elections in Rhode Island