Does SUSY know about the Standard Model?
JA Dixon�- arXiv preprint arXiv:1304.2036, 2013 - arxiv.org
JA Dixon
arXiv preprint arXiv:1304.2036, 2013•arxiv.orgThe BRST cohomology of free chiral SUSY has a wealth of Extraordinary Invariants. When
one adds a superpotential to the free theory, the extention of the Extraordinary Invariants
leads to some constraints on that superpotential. A particularly simple solution of those
constraints is based on a $3\times 3$ matrix of nine chiral superfields, and then the
superpotential is simply the determinant of that matrix. It is remarkable that this same theory
is also a plausible basic version of the SUSY Standard Model for one Lepton family, and�…
one adds a superpotential to the free theory, the extention of the Extraordinary Invariants
leads to some constraints on that superpotential. A particularly simple solution of those
constraints is based on a $3\times 3$ matrix of nine chiral superfields, and then the
superpotential is simply the determinant of that matrix. It is remarkable that this same theory
is also a plausible basic version of the SUSY Standard Model for one Lepton family, and�…
The BRST cohomology of free chiral SUSY has a wealth of Extraordinary Invariants. When one adds a superpotential to the free theory, the extention of the Extraordinary Invariants leads to some constraints on that superpotential. A particularly simple solution of those constraints is based on a matrix of nine chiral superfields, and then the superpotential is simply the determinant of that matrix. It is remarkable that this same theory is also a plausible basic version of the SUSY Standard Model for one Lepton family, and then the nine superfields are seen to be a left (Weak) SU(2) Lepton Doublet, Two Higgs Doublets, a Right Electron Singlet, a Right Neutrino Singlet and a Higgs singlet. Moreover, the algebra is consistent with the notion that the other two observed Lepton families arise from the coupling of the Extraordinary Invariants.
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