Abstract
We prove that Nash mapping is bijective for any surface defined over an algebraically closed field of characteristic $0$.
We prove that Nash mapping is bijective for any surface defined over an algebraically closed field of characteristic $0$.
ICMAT
CSIC-UAM-UCM-UC3M
28040 Madrid
Spain
ICMAT
CSIC-UAM-UCM-UC3M
28040 Madrid
Spain